3.1.9 \(\int (a+b x^2) (c+d x^2)^2 (e+f x^2)^3 \, dx\) [9]

Optimal. Leaf size=226 \[ a c^2 e^3 x+\frac {1}{3} c e^2 (b c e+2 a d e+3 a c f) x^3+\frac {1}{5} e \left (b c e (2 d e+3 c f)+a \left (d^2 e^2+6 c d e f+3 c^2 f^2\right )\right ) x^5+\frac {1}{7} \left (a f \left (3 d^2 e^2+6 c d e f+c^2 f^2\right )+b e \left (d^2 e^2+6 c d e f+3 c^2 f^2\right )\right ) x^7+\frac {1}{9} f \left (a d f (3 d e+2 c f)+b \left (3 d^2 e^2+6 c d e f+c^2 f^2\right )\right ) x^9+\frac {1}{11} d f^2 (3 b d e+2 b c f+a d f) x^{11}+\frac {1}{13} b d^2 f^3 x^{13} \]

[Out]

a*c^2*e^3*x+1/3*c*e^2*(3*a*c*f+2*a*d*e+b*c*e)*x^3+1/5*e*(b*c*e*(3*c*f+2*d*e)+a*(3*c^2*f^2+6*c*d*e*f+d^2*e^2))*
x^5+1/7*(a*f*(c^2*f^2+6*c*d*e*f+3*d^2*e^2)+b*e*(3*c^2*f^2+6*c*d*e*f+d^2*e^2))*x^7+1/9*f*(a*d*f*(2*c*f+3*d*e)+b
*(c^2*f^2+6*c*d*e*f+3*d^2*e^2))*x^9+1/11*d*f^2*(a*d*f+2*b*c*f+3*b*d*e)*x^11+1/13*b*d^2*f^3*x^13

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Rubi [A]
time = 0.14, antiderivative size = 226, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.038, Rules used = {535} \begin {gather*} \frac {1}{9} f x^9 \left (a d f (2 c f+3 d e)+b \left (c^2 f^2+6 c d e f+3 d^2 e^2\right )\right )+\frac {1}{7} x^7 \left (a f \left (c^2 f^2+6 c d e f+3 d^2 e^2\right )+b e \left (3 c^2 f^2+6 c d e f+d^2 e^2\right )\right )+\frac {1}{5} e x^5 \left (a \left (3 c^2 f^2+6 c d e f+d^2 e^2\right )+b c e (3 c f+2 d e)\right )+\frac {1}{3} c e^2 x^3 (3 a c f+2 a d e+b c e)+\frac {1}{11} d f^2 x^{11} (a d f+2 b c f+3 b d e)+a c^2 e^3 x+\frac {1}{13} b d^2 f^3 x^{13} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*x^2)*(c + d*x^2)^2*(e + f*x^2)^3,x]

[Out]

a*c^2*e^3*x + (c*e^2*(b*c*e + 2*a*d*e + 3*a*c*f)*x^3)/3 + (e*(b*c*e*(2*d*e + 3*c*f) + a*(d^2*e^2 + 6*c*d*e*f +
3*c^2*f^2))*x^5)/5 + ((a*f*(3*d^2*e^2 + 6*c*d*e*f + c^2*f^2) + b*e*(d^2*e^2 + 6*c*d*e*f + 3*c^2*f^2))*x^7)/7
+ (f*(a*d*f*(3*d*e + 2*c*f) + b*(3*d^2*e^2 + 6*c*d*e*f + c^2*f^2))*x^9)/9 + (d*f^2*(3*b*d*e + 2*b*c*f + a*d*f)
*x^11)/11 + (b*d^2*f^3*x^13)/13

Rule 535

Int[((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.)*((e_) + (f_.)*(x_)^(n_))^(r_.), x_Symbol] :>
Int[ExpandIntegrand[(a + b*x^n)^p*(c + d*x^n)^q*(e + f*x^n)^r, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && I
GtQ[p, 0] && IGtQ[q, 0] && IGtQ[r, 0]

Rubi steps

\begin {align*} \int \left (a+b x^2\right ) \left (c+d x^2\right )^2 \left (e+f x^2\right )^3 \, dx &=\int \left (a c^2 e^3+c e^2 (b c e+2 a d e+3 a c f) x^2+e \left (b c e (2 d e+3 c f)+a \left (d^2 e^2+6 c d e f+3 c^2 f^2\right )\right ) x^4+\left (a f \left (3 d^2 e^2+6 c d e f+c^2 f^2\right )+b e \left (d^2 e^2+6 c d e f+3 c^2 f^2\right )\right ) x^6+f \left (a d f (3 d e+2 c f)+b \left (3 d^2 e^2+6 c d e f+c^2 f^2\right )\right ) x^8+d f^2 (3 b d e+2 b c f+a d f) x^{10}+b d^2 f^3 x^{12}\right ) \, dx\\ &=a c^2 e^3 x+\frac {1}{3} c e^2 (b c e+2 a d e+3 a c f) x^3+\frac {1}{5} e \left (b c e (2 d e+3 c f)+a \left (d^2 e^2+6 c d e f+3 c^2 f^2\right )\right ) x^5+\frac {1}{7} \left (a f \left (3 d^2 e^2+6 c d e f+c^2 f^2\right )+b e \left (d^2 e^2+6 c d e f+3 c^2 f^2\right )\right ) x^7+\frac {1}{9} f \left (a d f (3 d e+2 c f)+b \left (3 d^2 e^2+6 c d e f+c^2 f^2\right )\right ) x^9+\frac {1}{11} d f^2 (3 b d e+2 b c f+a d f) x^{11}+\frac {1}{13} b d^2 f^3 x^{13}\\ \end {align*}

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Mathematica [A]
time = 0.06, size = 226, normalized size = 1.00 \begin {gather*} a c^2 e^3 x+\frac {1}{3} c e^2 (b c e+2 a d e+3 a c f) x^3+\frac {1}{5} e \left (b c e (2 d e+3 c f)+a \left (d^2 e^2+6 c d e f+3 c^2 f^2\right )\right ) x^5+\frac {1}{7} \left (a f \left (3 d^2 e^2+6 c d e f+c^2 f^2\right )+b e \left (d^2 e^2+6 c d e f+3 c^2 f^2\right )\right ) x^7+\frac {1}{9} f \left (a d f (3 d e+2 c f)+b \left (3 d^2 e^2+6 c d e f+c^2 f^2\right )\right ) x^9+\frac {1}{11} d f^2 (3 b d e+2 b c f+a d f) x^{11}+\frac {1}{13} b d^2 f^3 x^{13} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x^2)*(c + d*x^2)^2*(e + f*x^2)^3,x]

[Out]

a*c^2*e^3*x + (c*e^2*(b*c*e + 2*a*d*e + 3*a*c*f)*x^3)/3 + (e*(b*c*e*(2*d*e + 3*c*f) + a*(d^2*e^2 + 6*c*d*e*f +
3*c^2*f^2))*x^5)/5 + ((a*f*(3*d^2*e^2 + 6*c*d*e*f + c^2*f^2) + b*e*(d^2*e^2 + 6*c*d*e*f + 3*c^2*f^2))*x^7)/7
+ (f*(a*d*f*(3*d*e + 2*c*f) + b*(3*d^2*e^2 + 6*c*d*e*f + c^2*f^2))*x^9)/9 + (d*f^2*(3*b*d*e + 2*b*c*f + a*d*f)
*x^11)/11 + (b*d^2*f^3*x^13)/13

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Maple [A]
time = 0.17, size = 237, normalized size = 1.05

method	result	size
default	\(\frac {b \,d^{2} f^{3} x^{13}}{13}+\frac {\left (\left (a \,d^{2}+2 b c d \right ) f^{3}+3 b \,d^{2} e \,f^{2}\right ) x^{11}}{11}+\frac {\left (\left (2 a c d +b \,c^{2}\right ) f^{3}+3 \left (a \,d^{2}+2 b c d \right ) e \,f^{2}+3 b \,d^{2} e^{2} f \right ) x^{9}}{9}+\frac {\left (c^{2} a \,f^{3}+3 \left (2 a c d +b \,c^{2}\right ) e \,f^{2}+3 \left (a \,d^{2}+2 b c d \right ) e^{2} f +b \,d^{2} e^{3}\right ) x^{7}}{7}+\frac {\left (3 c^{2} a e \,f^{2}+3 \left (2 a c d +b \,c^{2}\right ) e^{2} f +\left (a \,d^{2}+2 b c d \right ) e^{3}\right ) x^{5}}{5}+\frac {\left (3 c^{2} a \,e^{2} f +\left (2 a c d +b \,c^{2}\right ) e^{3}\right ) x^{3}}{3}+a \,c^{2} e^{3} x\)	\(237\)
norman	\(\frac {b \,d^{2} f^{3} x^{13}}{13}+\left (\frac {1}{11} a \,d^{2} f^{3}+\frac {2}{11} b c d \,f^{3}+\frac {3}{11} b \,d^{2} e \,f^{2}\right ) x^{11}+\left (\frac {2}{9} a c d \,f^{3}+\frac {1}{3} a \,d^{2} e \,f^{2}+\frac {1}{9} b \,c^{2} f^{3}+\frac {2}{3} b c d e \,f^{2}+\frac {1}{3} b \,d^{2} e^{2} f \right ) x^{9}+\left (\frac {1}{7} c^{2} a \,f^{3}+\frac {6}{7} a c d e \,f^{2}+\frac {3}{7} a \,d^{2} e^{2} f +\frac {3}{7} b \,c^{2} e \,f^{2}+\frac {6}{7} b c d \,e^{2} f +\frac {1}{7} b \,d^{2} e^{3}\right ) x^{7}+\left (\frac {3}{5} c^{2} a e \,f^{2}+\frac {6}{5} a c d \,e^{2} f +\frac {1}{5} a \,d^{2} e^{3}+\frac {3}{5} b \,c^{2} e^{2} f +\frac {2}{5} b c d \,e^{3}\right ) x^{5}+\left (c^{2} a \,e^{2} f +\frac {2}{3} a c d \,e^{3}+\frac {1}{3} b \,c^{2} e^{3}\right ) x^{3}+a \,c^{2} e^{3} x\)	\(249\)
gosper	\(\frac {1}{13} b \,d^{2} f^{3} x^{13}+\frac {1}{11} x^{11} a \,d^{2} f^{3}+\frac {2}{11} x^{11} b c d \,f^{3}+\frac {3}{11} x^{11} b \,d^{2} e \,f^{2}+\frac {2}{9} x^{9} a c d \,f^{3}+\frac {1}{3} x^{9} a \,d^{2} e \,f^{2}+\frac {1}{9} x^{9} b \,c^{2} f^{3}+\frac {2}{3} x^{9} b c d e \,f^{2}+\frac {1}{3} x^{9} b \,d^{2} e^{2} f +\frac {1}{7} x^{7} c^{2} a \,f^{3}+\frac {6}{7} x^{7} a c d e \,f^{2}+\frac {3}{7} x^{7} a \,d^{2} e^{2} f +\frac {3}{7} x^{7} b \,c^{2} e \,f^{2}+\frac {6}{7} x^{7} b c d \,e^{2} f +\frac {1}{7} x^{7} b \,d^{2} e^{3}+\frac {3}{5} x^{5} c^{2} a e \,f^{2}+\frac {6}{5} x^{5} a c d \,e^{2} f +\frac {1}{5} x^{5} a \,d^{2} e^{3}+\frac {3}{5} x^{5} b \,c^{2} e^{2} f +\frac {2}{5} x^{5} b c d \,e^{3}+x^{3} c^{2} a \,e^{2} f +\frac {2}{3} x^{3} a c d \,e^{3}+\frac {1}{3} x^{3} b \,c^{2} e^{3}+a \,c^{2} e^{3} x\)	\(290\)
risch	\(\frac {1}{13} b \,d^{2} f^{3} x^{13}+\frac {1}{11} x^{11} a \,d^{2} f^{3}+\frac {2}{11} x^{11} b c d \,f^{3}+\frac {3}{11} x^{11} b \,d^{2} e \,f^{2}+\frac {2}{9} x^{9} a c d \,f^{3}+\frac {1}{3} x^{9} a \,d^{2} e \,f^{2}+\frac {1}{9} x^{9} b \,c^{2} f^{3}+\frac {2}{3} x^{9} b c d e \,f^{2}+\frac {1}{3} x^{9} b \,d^{2} e^{2} f +\frac {1}{7} x^{7} c^{2} a \,f^{3}+\frac {6}{7} x^{7} a c d e \,f^{2}+\frac {3}{7} x^{7} a \,d^{2} e^{2} f +\frac {3}{7} x^{7} b \,c^{2} e \,f^{2}+\frac {6}{7} x^{7} b c d \,e^{2} f +\frac {1}{7} x^{7} b \,d^{2} e^{3}+\frac {3}{5} x^{5} c^{2} a e \,f^{2}+\frac {6}{5} x^{5} a c d \,e^{2} f +\frac {1}{5} x^{5} a \,d^{2} e^{3}+\frac {3}{5} x^{5} b \,c^{2} e^{2} f +\frac {2}{5} x^{5} b c d \,e^{3}+x^{3} c^{2} a \,e^{2} f +\frac {2}{3} x^{3} a c d \,e^{3}+\frac {1}{3} x^{3} b \,c^{2} e^{3}+a \,c^{2} e^{3} x\)	\(290\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^2+a)*(d*x^2+c)^2*(f*x^2+e)^3,x,method=_RETURNVERBOSE)

[Out]

1/13*b*d^2*f^3*x^13+1/11*((a*d^2+2*b*c*d)*f^3+3*b*d^2*e*f^2)*x^11+1/9*((2*a*c*d+b*c^2)*f^3+3*(a*d^2+2*b*c*d)*e
*f^2+3*b*d^2*e^2*f)*x^9+1/7*(c^2*a*f^3+3*(2*a*c*d+b*c^2)*e*f^2+3*(a*d^2+2*b*c*d)*e^2*f+b*d^2*e^3)*x^7+1/5*(3*c
^2*a*e*f^2+3*(2*a*c*d+b*c^2)*e^2*f+(a*d^2+2*b*c*d)*e^3)*x^5+1/3*(3*c^2*a*e^2*f+(2*a*c*d+b*c^2)*e^3)*x^3+a*c^2*
e^3*x

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Maxima [A]
time = 0.27, size = 240, normalized size = 1.06 \begin {gather*} \frac {1}{13} \, b d^{2} f^{3} x^{13} + \frac {1}{11} \, {\left (3 \, b d^{2} f^{2} e + {\left (2 \, b c d + a d^{2}\right )} f^{3}\right )} x^{11} + \frac {1}{9} \, {\left (3 \, b d^{2} f e^{2} + {\left (b c^{2} + 2 \, a c d\right )} f^{3} + 3 \, {\left (2 \, b c d e + a d^{2} e\right )} f^{2}\right )} x^{9} + \frac {1}{7} \, {\left (a c^{2} f^{3} + b d^{2} e^{3} + 3 \, {\left (b c^{2} e + 2 \, a c d e\right )} f^{2} + 3 \, {\left (2 \, b c d e^{2} + a d^{2} e^{2}\right )} f\right )} x^{7} + \frac {1}{5} \, {\left (3 \, a c^{2} f^{2} e + 2 \, b c d e^{3} + a d^{2} e^{3} + 3 \, {\left (b c^{2} e^{2} + 2 \, a c d e^{2}\right )} f\right )} x^{5} + a c^{2} x e^{3} + \frac {1}{3} \, {\left (3 \, a c^{2} f e^{2} + b c^{2} e^{3} + 2 \, a c d e^{3}\right )} x^{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)*(d*x^2+c)^2*(f*x^2+e)^3,x, algorithm="maxima")

[Out]

1/13*b*d^2*f^3*x^13 + 1/11*(3*b*d^2*f^2*e + (2*b*c*d + a*d^2)*f^3)*x^11 + 1/9*(3*b*d^2*f*e^2 + (b*c^2 + 2*a*c*
d)*f^3 + 3*(2*b*c*d*e + a*d^2*e)*f^2)*x^9 + 1/7*(a*c^2*f^3 + b*d^2*e^3 + 3*(b*c^2*e + 2*a*c*d*e)*f^2 + 3*(2*b*
c*d*e^2 + a*d^2*e^2)*f)*x^7 + 1/5*(3*a*c^2*f^2*e + 2*b*c*d*e^3 + a*d^2*e^3 + 3*(b*c^2*e^2 + 2*a*c*d*e^2)*f)*x^
5 + a*c^2*x*e^3 + 1/3*(3*a*c^2*f*e^2 + b*c^2*e^3 + 2*a*c*d*e^3)*x^3

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Fricas [A]
time = 0.88, size = 242, normalized size = 1.07 \begin {gather*} \frac {1}{13} \, b d^{2} f^{3} x^{13} + \frac {1}{11} \, {\left (2 \, b c d + a d^{2}\right )} f^{3} x^{11} + \frac {1}{7} \, a c^{2} f^{3} x^{7} + \frac {1}{9} \, {\left (b c^{2} + 2 \, a c d\right )} f^{3} x^{9} + \frac {1}{105} \, {\left (15 \, b d^{2} x^{7} + 21 \, {\left (2 \, b c d + a d^{2}\right )} x^{5} + 105 \, a c^{2} x + 35 \, {\left (b c^{2} + 2 \, a c d\right )} x^{3}\right )} e^{3} + \frac {1}{105} \, {\left (35 \, b d^{2} f x^{9} + 45 \, {\left (2 \, b c d + a d^{2}\right )} f x^{7} + 105 \, a c^{2} f x^{3} + 63 \, {\left (b c^{2} + 2 \, a c d\right )} f x^{5}\right )} e^{2} + \frac {1}{1155} \, {\left (315 \, b d^{2} f^{2} x^{11} + 385 \, {\left (2 \, b c d + a d^{2}\right )} f^{2} x^{9} + 693 \, a c^{2} f^{2} x^{5} + 495 \, {\left (b c^{2} + 2 \, a c d\right )} f^{2} x^{7}\right )} e \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)*(d*x^2+c)^2*(f*x^2+e)^3,x, algorithm="fricas")

[Out]

1/13*b*d^2*f^3*x^13 + 1/11*(2*b*c*d + a*d^2)*f^3*x^11 + 1/7*a*c^2*f^3*x^7 + 1/9*(b*c^2 + 2*a*c*d)*f^3*x^9 + 1/
105*(15*b*d^2*x^7 + 21*(2*b*c*d + a*d^2)*x^5 + 105*a*c^2*x + 35*(b*c^2 + 2*a*c*d)*x^3)*e^3 + 1/105*(35*b*d^2*f
*x^9 + 45*(2*b*c*d + a*d^2)*f*x^7 + 105*a*c^2*f*x^3 + 63*(b*c^2 + 2*a*c*d)*f*x^5)*e^2 + 1/1155*(315*b*d^2*f^2*
x^11 + 385*(2*b*c*d + a*d^2)*f^2*x^9 + 693*a*c^2*f^2*x^5 + 495*(b*c^2 + 2*a*c*d)*f^2*x^7)*e

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Sympy [A]
time = 0.03, size = 304, normalized size = 1.35 \begin {gather*} a c^{2} e^{3} x + \frac {b d^{2} f^{3} x^{13}}{13} + x^{11} \left (\frac {a d^{2} f^{3}}{11} + \frac {2 b c d f^{3}}{11} + \frac {3 b d^{2} e f^{2}}{11}\right ) + x^{9} \cdot \left (\frac {2 a c d f^{3}}{9} + \frac {a d^{2} e f^{2}}{3} + \frac {b c^{2} f^{3}}{9} + \frac {2 b c d e f^{2}}{3} + \frac {b d^{2} e^{2} f}{3}\right ) + x^{7} \left (\frac {a c^{2} f^{3}}{7} + \frac {6 a c d e f^{2}}{7} + \frac {3 a d^{2} e^{2} f}{7} + \frac {3 b c^{2} e f^{2}}{7} + \frac {6 b c d e^{2} f}{7} + \frac {b d^{2} e^{3}}{7}\right ) + x^{5} \cdot \left (\frac {3 a c^{2} e f^{2}}{5} + \frac {6 a c d e^{2} f}{5} + \frac {a d^{2} e^{3}}{5} + \frac {3 b c^{2} e^{2} f}{5} + \frac {2 b c d e^{3}}{5}\right ) + x^{3} \left (a c^{2} e^{2} f + \frac {2 a c d e^{3}}{3} + \frac {b c^{2} e^{3}}{3}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**2+a)*(d*x**2+c)**2*(f*x**2+e)**3,x)

[Out]

a*c**2*e**3*x + b*d**2*f**3*x**13/13 + x**11*(a*d**2*f**3/11 + 2*b*c*d*f**3/11 + 3*b*d**2*e*f**2/11) + x**9*(2
*a*c*d*f**3/9 + a*d**2*e*f**2/3 + b*c**2*f**3/9 + 2*b*c*d*e*f**2/3 + b*d**2*e**2*f/3) + x**7*(a*c**2*f**3/7 +
6*a*c*d*e*f**2/7 + 3*a*d**2*e**2*f/7 + 3*b*c**2*e*f**2/7 + 6*b*c*d*e**2*f/7 + b*d**2*e**3/7) + x**5*(3*a*c**2*
e*f**2/5 + 6*a*c*d*e**2*f/5 + a*d**2*e**3/5 + 3*b*c**2*e**2*f/5 + 2*b*c*d*e**3/5) + x**3*(a*c**2*e**2*f + 2*a*
c*d*e**3/3 + b*c**2*e**3/3)

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Giac [A]
time = 0.98, size = 283, normalized size = 1.25 \begin {gather*} \frac {1}{13} \, b d^{2} f^{3} x^{13} + \frac {2}{11} \, b c d f^{3} x^{11} + \frac {1}{11} \, a d^{2} f^{3} x^{11} + \frac {3}{11} \, b d^{2} f^{2} x^{11} e + \frac {1}{9} \, b c^{2} f^{3} x^{9} + \frac {2}{9} \, a c d f^{3} x^{9} + \frac {2}{3} \, b c d f^{2} x^{9} e + \frac {1}{3} \, a d^{2} f^{2} x^{9} e + \frac {1}{3} \, b d^{2} f x^{9} e^{2} + \frac {1}{7} \, a c^{2} f^{3} x^{7} + \frac {3}{7} \, b c^{2} f^{2} x^{7} e + \frac {6}{7} \, a c d f^{2} x^{7} e + \frac {6}{7} \, b c d f x^{7} e^{2} + \frac {3}{7} \, a d^{2} f x^{7} e^{2} + \frac {1}{7} \, b d^{2} x^{7} e^{3} + \frac {3}{5} \, a c^{2} f^{2} x^{5} e + \frac {3}{5} \, b c^{2} f x^{5} e^{2} + \frac {6}{5} \, a c d f x^{5} e^{2} + \frac {2}{5} \, b c d x^{5} e^{3} + \frac {1}{5} \, a d^{2} x^{5} e^{3} + a c^{2} f x^{3} e^{2} + \frac {1}{3} \, b c^{2} x^{3} e^{3} + \frac {2}{3} \, a c d x^{3} e^{3} + a c^{2} x e^{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)*(d*x^2+c)^2*(f*x^2+e)^3,x, algorithm="giac")

[Out]

1/13*b*d^2*f^3*x^13 + 2/11*b*c*d*f^3*x^11 + 1/11*a*d^2*f^3*x^11 + 3/11*b*d^2*f^2*x^11*e + 1/9*b*c^2*f^3*x^9 +
2/9*a*c*d*f^3*x^9 + 2/3*b*c*d*f^2*x^9*e + 1/3*a*d^2*f^2*x^9*e + 1/3*b*d^2*f*x^9*e^2 + 1/7*a*c^2*f^3*x^7 + 3/7*
b*c^2*f^2*x^7*e + 6/7*a*c*d*f^2*x^7*e + 6/7*b*c*d*f*x^7*e^2 + 3/7*a*d^2*f*x^7*e^2 + 1/7*b*d^2*x^7*e^3 + 3/5*a*
c^2*f^2*x^5*e + 3/5*b*c^2*f*x^5*e^2 + 6/5*a*c*d*f*x^5*e^2 + 2/5*b*c*d*x^5*e^3 + 1/5*a*d^2*x^5*e^3 + a*c^2*f*x^
3*e^2 + 1/3*b*c^2*x^3*e^3 + 2/3*a*c*d*x^3*e^3 + a*c^2*x*e^3

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Mupad [B]
time = 0.86, size = 233, normalized size = 1.03 \begin {gather*} x^5\,\left (\frac {3\,b\,c^2\,e^2\,f}{5}+\frac {3\,a\,c^2\,e\,f^2}{5}+\frac {2\,b\,c\,d\,e^3}{5}+\frac {6\,a\,c\,d\,e^2\,f}{5}+\frac {a\,d^2\,e^3}{5}\right )+x^9\,\left (\frac {b\,c^2\,f^3}{9}+\frac {2\,b\,c\,d\,e\,f^2}{3}+\frac {2\,a\,c\,d\,f^3}{9}+\frac {b\,d^2\,e^2\,f}{3}+\frac {a\,d^2\,e\,f^2}{3}\right )+x^7\,\left (\frac {3\,b\,c^2\,e\,f^2}{7}+\frac {a\,c^2\,f^3}{7}+\frac {6\,b\,c\,d\,e^2\,f}{7}+\frac {6\,a\,c\,d\,e\,f^2}{7}+\frac {b\,d^2\,e^3}{7}+\frac {3\,a\,d^2\,e^2\,f}{7}\right )+\frac {b\,d^2\,f^3\,x^{13}}{13}+\frac {c\,e^2\,x^3\,\left (3\,a\,c\,f+2\,a\,d\,e+b\,c\,e\right )}{3}+\frac {d\,f^2\,x^{11}\,\left (a\,d\,f+2\,b\,c\,f+3\,b\,d\,e\right )}{11}+a\,c^2\,e^3\,x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x^2)*(c + d*x^2)^2*(e + f*x^2)^3,x)

[Out]

x^5*((a*d^2*e^3)/5 + (2*b*c*d*e^3)/5 + (3*a*c^2*e*f^2)/5 + (3*b*c^2*e^2*f)/5 + (6*a*c*d*e^2*f)/5) + x^9*((b*c^
2*f^3)/9 + (2*a*c*d*f^3)/9 + (a*d^2*e*f^2)/3 + (b*d^2*e^2*f)/3 + (2*b*c*d*e*f^2)/3) + x^7*((a*c^2*f^3)/7 + (b*
d^2*e^3)/7 + (3*a*d^2*e^2*f)/7 + (3*b*c^2*e*f^2)/7 + (6*a*c*d*e*f^2)/7 + (6*b*c*d*e^2*f)/7) + (b*d^2*f^3*x^13)
/13 + (c*e^2*x^3*(3*a*c*f + 2*a*d*e + b*c*e))/3 + (d*f^2*x^11*(a*d*f + 2*b*c*f + 3*b*d*e))/11 + a*c^2*e^3*x

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